BacII Exam Result for all Provinces and Cities 2015

Here are the result of BacII exam 2015. Click on the following links to download:

1. Kompong Chhnang (Download Result)
2. Pailin (Download Result)
3. Kompong Thom (Download Result)
4. Kompong Cham (Download Result)
5. Prey Veng (Download Result)
6. Svay Rieng (Download Result)
7. Preah Vihear (Download Result)
8. Ratanakiri (Download Result)
9. Pursat (Download Result)
10. Kratie (Download Result)
11. Siem Reap (Download Result)
12. Battambang (Download Result)
13. Odormeanchey (Download Result)
14. Mondulkiri (Download Result)
15. Kompong Speu (Download Result)
16. Preah Sihanuk (Download Result)
17. Kep (Download Result)
18. Stoeung Trieng (Download Result)
19. Bonteay Meanchey (Download Result)
20. Koh Kong (Download Result)
21. Kampot (Download Result)
22. Takeo (Download Result)
23. Tbong Khmum (Download Result)
24. Kandal (Download Result)
25. Phnom Penh (Download Result)

Secondary Teacher Exam Collection 2002-2011

This is the collection of Secondary Teacher exam from 2002 to 2011. For those who want to take teacher exam have to review all these exercises because it may appear again in the exam.

Find the letters 9 x HATBOX = 4 x BOXHAT

Each letter must represent a digit from 1 to 9 with no two letters representing the same digit.

Solution

We have: 9 x HATBOX = 4 x BOXHAT

set "HAT" =x and "BOX"=y(x,y has 3-digit)

the equation becomes

9(1000x+y) = 4(1000y+x) or

8996x = 3991y

which on division by 13 becomes

692x = 307y

where the coefficients are relatively prime.

This has the obvious solution we can set as:

x = 307n, y = 692n for any integer n

The only solution in which x and y are both 3-digit numbers is for

n = 1. Then

     HAT = 307

     BOX = 692

     9(HATBOX) = 9(307692) = 2769228

     4(BOXHAT) = 4(692307) = 2769228

Thus: H=3,A=0,T=7,B=6,O=9,X=2

Bell Problem

A first bell ring at every 6 minutes, a second bell rings every 7 minutes and a third bell rings every 1 hour, if all the bells start ringing at 12 noon today when the next day will all ring at the same time?

Solution

-The 1st two bells will ring at the same time every 6*7 = 42 mn

-The 3rd bell ring once every hour, or once every 60mn

-What is the smallest multiple of 42 that is evenly divided by 60?

(10*42)/60 = 420/60 =7

-So, every 420 min, all 3 bells ring together

420/60 = 7h

-12 noon : 12pm + 7h = 7pm is when they all ring together

Find the value of M

M is a positive number that follow these conditions:

• M is a number that 80<M<100 
• if M divided by 4 the remainder is 3 
• and if M divided by 5 the remainder is 1.

Find the value of M?

Solution:

• M divided by 4 gives remainder 3. So M can be written as 4r + 3 for some integer r
• M divided by 5 gives remainder 1. So M can be written as 5*t + 1 for some integer t

So M=4*r + 3 or M=5*t + 1

• But  80<M<100 

Thus 80<4*r + 3<100 , 77<4r<97 , 19.25<r<24.25 so r={20,21,22,23,24}

• r=20 => M=4*20+3=83 
• r=21 => M=4*21+3=87
• r=22 => M=4*22+3=91
• r=23 => M=4*23+3=95
• r=24 => M=4*24+3=99

Only r=22 that M=91 can be written as 91=5*18+1  so the only one value of M=91 that apply to these two forms.

Math Problem of the Day

Spend about 10 seconds, what is the value of A. It is not too hard to think. Let say the value of  A!

Find the value of x^2 + y^2

Let x+y=1 and x^3+y^3=19

Find the value of x^2 + y^2?

Answer

We have x^3 + y^3=(x+y)(x^2 - xy + y^2) = 19

and x+y = 1 Thus x^2 - xy + y^2 = 19

and also we can write as 2x^2 + 2y^2 - 2xy = 38(1)

Then also (x+y)^2 = x^2 + y^2 + 2xy = 1(2)

Adding (1) and (2):

We get 3x^2 + 3y^2 = 39

so that  x^2 + y^2 = 13